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Where \(f(x) = 0\), evaluate the indefinite integral: \[\int f(x)\,\mathrm dx\]
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um let me think so............
derivative of a constant is 0, so antiderivative of 0 must be a constant ?
Yes, integrating 0 is C
(and why does a diagram give the wrong conclusion)
what Diagram ?
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|dw:1438851830406:dw| a rectangle of height zero , how can the area be anything other than zero?
but it is right that integrating 0 is C
if it were a definite integral, it will always equal zero |dw:1438851890255:dw|
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