Solve the system of equations.

x + 3y = −1
2x + 2y = 6

(−4, 1)
(2, −1)
(4, −1)
(5, −2)

Question

Solve the system of equations.

x + 3y = −1
2x + 2y = 6

 (−4, 1)
 (2, −1)
 (4, −1)
 (5, −2)

anonymous · Answer

@Michele_Laino can u help me

mathstudent55 · Answer

Do you have a preferred method, substitution, addition, etc.?

anonymous · Answer

Use the substitution method and isolate x in the first equation.

x + 3y = -1
x + 3y - 3y = -1 - 3y
x = -1 - 3y

After you've isolated x, plug in what x equals onto the second equation.

2x + 2y = 6
2(-1 - 3y) + 2y = 6

Distribute the expression in parenthesis. Next, combine all like terms and solve for y.

If you've received y, just plug it back in the first original equation to receive the value of x.

That will be your (x, y) value, or your solution.

anonymous · Answer

Type both equations in this link. It will show you the steps. http://www.mathpapa.com/calc.html?q=x+y%3D7%2C%20x+2y%3D11

anonymous · Answer

@Q345