Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (mathmath333):

Question

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} & \normalsize \text{Find the number of ways or rearranging the word}\quad \Large \rm INSTITUTE\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (anonymous):

This is a permutation

OpenStudy (anonymous):

9*8*7*6*5*4*3*2*1=

OpenStudy (anonymous):

That's your answer bro

OpenStudy (mathmath333):

u mean \(\large 9!\)

OpenStudy (anonymous):

yeah I do

OpenStudy (phi):

you have to account for repeated letters

OpenStudy (anonymous):

That's why it's 9 exclamation happy mathy day

OpenStudy (mathmath333):

hmm that is given as wrong

OpenStudy (rhr12):

Opps!! Idk what is that.

OpenStudy (freckles):

\[\frac{ \text{ total number of letters }!}{\text{ repetitions of letter i}!}\] where i can be a,b,c,....z

OpenStudy (freckles):

for example if we had the word ball it would be 4!/2!

OpenStudy (freckles):

or if we had the word mississippi it would be \[\frac{11!}{4! \cdot 4! \cdot 2!}\]

OpenStudy (freckles):

where one of those 4's account for the amount of s the other 4 account for the amount of i and where 2 account for the amount of p

OpenStudy (mathmath333):

(9/2*3)!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!