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OpenStudy (mathmath333):
\(\large \color{black}{\begin{align}
& \normalsize \text{Find the number of ways or rearranging the word}\quad \Large \rm INSTITUTE\hspace{.33em}\\~\\
\end{align}}\)
OpenStudy (anonymous):
This is a permutation
OpenStudy (anonymous):
9*8*7*6*5*4*3*2*1=
OpenStudy (anonymous):
That's your answer bro
OpenStudy (mathmath333):
u mean \(\large 9!\)
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OpenStudy (anonymous):
yeah I do
OpenStudy (phi):
you have to account for repeated letters
OpenStudy (anonymous):
That's why it's 9 exclamation happy mathy day
OpenStudy (mathmath333):
hmm that is given as wrong
OpenStudy (rhr12):
Opps!! Idk what is that.
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OpenStudy (freckles):
\[\frac{ \text{ total number of letters }!}{\text{ repetitions of letter i}!}\]
where i can be a,b,c,....z
OpenStudy (freckles):
for example if we had the word ball it would be
4!/2!
OpenStudy (freckles):
or if we had the word mississippi
it would be
\[\frac{11!}{4! \cdot 4! \cdot 2!}\]
OpenStudy (freckles):
where one of those 4's account for the amount of s
the other 4 account for the amount of i
and where 2 account for the amount of p