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Tiffany kicks a soccer ball off the ground and in the air, with an initial velocity of 28 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches? 15.6 feet 14.1 feet 13.5 feet 12.3 feet
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12.3 feet
first put 28 for v \(h(t)=-16t^2+28+0\)
I think it is 12.3 feet
yea it's 12.3
Initial height is 0, we can take the derivative \[h'(t) = -32t+28 \] set it equal to 0 to find the time, so we get \[t = 0.875s\] now we can plug it into the original equation, that will give you the maximum height.
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