Write the equation of the line, in standard form, that passes through the origin and is parallel to x + y = 6. Include your work in your final answer.

I understand the answer is x + y = 0
I want to understand how that is determined. Using point slope form and all that.

Question

Write the equation of the line, in standard form, that passes through the origin and is parallel to x + y = 6. Include your work in your final answer. 

I understand the answer is x + y = 0
I want to understand how that is determined. Using point slope form and all that.

campbell_st · Answer

well it needs an x intercept of 0 and y intercept of 0 and slope of -1

so if you take the given line 

x + y = 6

then 

y = -x + 6

so the slope if m = -1

the point is the origin (0,0)

then 

y - 0 = -1(x - 0)

just simplify

anonymous · Answer

So you determine the slope by the points?

campbell_st · Answer

the slope comes from the original line

its in standard form 

x + y = 6

re=writing in slope intercept form 

y = -x + 6

campbell_st · Answer

so the slope is m = -1

anonymous · Answer

Okay so the -x is the slope? What about the 6? Does it not do anything?

campbell_st · Answer

no the slope is -1

the general slope intercept form is 

y = mx + b        m is the slope  so in the given line m = -1     b is the y-intercept

anonymous · Answer

Oh I see what I was doing. Thank you. I understand.