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Mathematics 16 Online
OpenStudy (redheadangel):

The cross-sectional area parallel to the bases of the two figures above is the same at every level. Find the volume of the cone, to the nearest tenth.

OpenStudy (redheadangel):

OpenStudy (redheadangel):

I have no idea where to even start

OpenStudy (redheadangel):

@Peaches15 @LexiLuvv2431

OpenStudy (redheadangel):

@campbell_st

OpenStudy (redheadangel):

@welshfella

OpenStudy (anonymous):

I suckkk at math. I can't really help you here :/ sorry

OpenStudy (redheadangel):

that's okay thanks tho :) @LexiLuvv2431

OpenStudy (anonymous):

@redheadangel I don't know dis kin of math sorry

OpenStudy (redheadangel):

That's okay thanks @Peaches15

OpenStudy (redheadangel):

@Kitten_is_back

OpenStudy (redheadangel):

@Hero ppppplleasssee I will fan and medal I promise

OpenStudy (itsmichelle29):

Volume cone v =1/3 pi r^2 * h

OpenStudy (itsmichelle29):

Volume Triangular pyramid v=1/3 b*h

OpenStudy (redheadangel):

Yes, I am just confused on how to find all of the measurments for the cone

OpenStudy (redheadangel):

@Owlcoffee p.l.e.a.s.e and t.h.a.n.k y.o.u

OpenStudy (redheadangel):

@DanJS g.r.a.c.i.a.s

OpenStudy (owlcoffee):

Okay, this is a little tricky one, but I think I have fully understood it. On the left side we have a pyramid that has a triangular base and on the right side, a cone which has a circular base. Both heights are the same, and we are given some information about the base of the pyramid, you can view it as a triangle which you'll have to find the missing side: |dw:1438983224810:dw| So, try finding the area of that triangle and that'd be the first step on getting it solved. Because we know, as given information, that the area of the base on the pyramid is the same as the area of the base on the cone.

OpenStudy (redheadangel):

so for the missing side I got 3.6

OpenStudy (redheadangel):

I got that the area 8.64... is that right?

OpenStudy (redheadangel):

@Owlcoffee

OpenStudy (redheadangel):

@geerky42 perhaps you could help?

geerky42 (geerky42):

If cross-sectional areas are same for every level, this means they both have same height and same volume, right?

OpenStudy (redheadangel):

yes

geerky42 (geerky42):

So you just need to find volume of triangle pyramid.

OpenStudy (redheadangel):

ooohhh I see

geerky42 (geerky42):

So can you handle it from here?

OpenStudy (redheadangel):

Yes thank you so much I got 44.16 as the area

OpenStudy (redheadangel):

would you mind helping me with one more?

geerky42 (geerky42):

you need volume; formula is \(V=\dfrac{1}{3}Bh\) B is area of base

OpenStudy (redheadangel):

oh my gosh you're right idk what i was thinking lol

OpenStudy (redheadangel):

Yes I meant to say that, the volume is 44.16, just typed the wrong thing

geerky42 (geerky42):

well, I got 26.496 cm\(^3\)

geerky42 (geerky42):

did you multiply 4.8 by 6? because you shouldnt

OpenStudy (redheadangel):

honestly I typed it into one of those volume calculators and thats what it came up with

OpenStudy (redheadangel):

but your answer is one of the answer choices, so maybe mine was wrong

geerky42 (geerky42):

for area of triangle, you need base and height. 4.8 can be height, so you need to find length of base. You can use Pythagorean theorem here.

geerky42 (geerky42):

|dw:1438984981177:dw|

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