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Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement? 6.45% 7.50% 9.12% 13.33%
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https://www.mathsisfun.com/numbers/percentage-error.html \[\large \text{percent error} = \frac{| \text{approximate value}-\text{exact value}|}{|\text{exact value}|} \ \times 100\%\]
5.55 - 6/6 x 100?
I think you meant to say \[\Large \text{percent error} = \frac{| 5.55-6|}{|6|} \times 100\%\] right?
i got -94.45...
what is 5.55 - 6 equal to?
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-0.45
|-0.45| = 0.45
divide that by 6 then multiply by 100 to convert to a percentage
is it b?
yes
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i got 7.50
me too
ok thank you :)
7.50%
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