Create a rational function with a linear binomial in both the numerator and denominator. Part 1. Graph your function using technology. Include the horizontal and vertical asymptotes and the x- and y-intercepts on your graph. Label the asymptotes and intercepts. Part 2. Show all work to identify the vertical asymptote, the x-intercepts, and the y-intercept.
@welshfella @LynFran
@adxpoi
ax + b ------ cx - d plug in values for a b c and d ( not = 0)
a=1 b=2 c=3 d4? is that good? @welshfella srry i was inactive :(
yes so we have x + 2 ----- 3x + 4 you can use desmos to graph this
https://www.desmos.com/calculator/5qfhpf8bgt asymptotes are breaks in the graph
you see that the x intercept is at (-2,0)
ok
what is the y-intercept
0.5
x= -2
y = 0.5 they want the coordinates of the point which is x = 0 y = 0.5 or (0,0.5)
ok
y intercept is at ( 0 , 0.5)
ok
now the vertical asymptote is the line between where the vertical parts of the go 'off the page'
thats between x = -1 and x = -2 and its difficult to get from the graph vertical asymptotes occur when the denominator is zero so we can work it ouT:- 3x + 4 = 0 3x = -4 x = -4/3 or about -1.33
should i put x-intercept also ?
yea we 've done that
to work it out we put (x + 2) / (3x + 4) = 0 so x+ 2 = o and x = -2 x intercept at (-2 , 0)
how would you work out the intercept
*y-intercept
put x = 0 in ( x +2) / (3x + 4)
because at the intercepts x = 0
so (0+2) /3(0) + 4)? (2)/ (0+4) 2/4 1/2?
yes - which is what we read off on the graph
and also the vertic asymptotes is -4/3 OR about -1.33 right but what about the horizontal ?
i cant remember !! lol hold on
and ok :)
srry I'm throwing everything @ you!
i gotta go right now as you see form the graph its about y = 0.6
really quick whats the horizontal retricem and show me plesase who to solve
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