Question

@Loser66 What is the length of the tangent to the circle

(x+2)^2 + (y-3)^2 = 4 drawn from the point A(6,0) ?

Answer 1

I will ask calculus as well

Answer 2

yes

Answer 3

d= in root (x1-x2)^2 + (y1-y2)^2

Answer 4

ohhhh ok then which will be

Answer 5

root 73 but I dont have it at the answers

Answer 6

ohhhh sorry its 5

Answer 7

thank you man

Answer 8

I owe you

Answer 9

can you help me more please :D

Answer 10

I just dont know how to draw or make a snapchat for the questions

Answer 11

yes

Answer 12

yeah but it is not root 73

Answer 13

its 5 I think

Answer 14

oopppssss my bad its root 73

Answer 15

there has been a mistake mate . it was A(-6,0)
sorry for that

Answer 16

yeah but I didnt understand that part how you found the radius

Answer 17

ohhh ok you mean its from the centre

Answer 18

right ?

Answer 19

ok so OB is 2 with pythagoras it will be

Answer 20

just one more question

Answer 21

the answer will be root 21

Answer 22

but why the 90 degree became what you called as B ?

Answer 23

Yoou mean because of the tangent

Answer 24

which passes through the circle always make it 90 degrees .

Answer 25

Thanks a lot men . Do you mind If I will ask you more questions . Because I really do need your help for my exam

Answer 26

thanks mate

Answer 27

to here

Answer 28

or?

Answer 29

here

Answer 30

I will delete the previous problem to save the time to scroll down, ok?

Answer 31

ok
The remainders when a polynomial P(x) is divided by x-2 and x+1 are respectively 3 and -2. The remainder when P(x) is divided by (x^2-x-2)is K(x). What is the value of K(-4) ?

Answer 32

Did you get the question ?

Answer 33

Yes, I am thinking.

Answer 34

ok.

Answer 35

anything :D

Answer 36

I don't know.

Answer 37

you mean you cant solve this one

Answer 38

I have one more probability if you would like