Question

Find the slope of the tangent line to the polar curve r=sin(4θ) at θ=π/8.

Answer 1

this page may be of help

http://tutorial.math.lamar.edu/Classes/CalcII/PolarTangents.aspx

Answer 2

still am confused

Answer 3

where are you stuck in the article?

Answer 4

it has cos and ii am trying to find (sin) in my problem

Answer 5

x = r*cos(theta)

x = sin(4theta) * cos(theta) ... replace 'r' with 'sin(4theta)'

what do you get when you derive both sides with respect to theta?

Answer 6

r/r*cos ??

Answer 7

if the theta's are throwing you off, then think of them as x

ie think of it as

y = sin(4x)*cos(x)

what is dy/dx here?

Answer 8

idk

Answer 9

use the product and chain rule here