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Mathematics 17 Online
OpenStudy (anonymous):

If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below. 17 23 −17 −23

Nnesha (nnesha):

first find j(2) substitute x for 2 into j(x) function

OpenStudy (anonymous):

So the answer would end up to be C?

Nnesha (nnesha):

how ?? hm

Nnesha (nnesha):

j(2) = ?

OpenStudy (anonymous):

(-2x)= \[-2\times2?\]

Nnesha (nnesha):

yes right j(2) = -2 times 2

OpenStudy (anonymous):

Which would = -4

Nnesha (nnesha):

now substitute x for j(2) value into h(x) function

OpenStudy (anonymous):

I am confused on this part....

Nnesha (nnesha):

hhaha alright so you need h[j(2)] j(2) =-4 so in other words you need h(-4) now substitute x for -4 into h(x) funtion

Nnesha (nnesha):

\[\huge\rm h(-4)=5\color{ReD}{x}-3\] replace x for -4 and then sovle!

Nnesha (nnesha):

solve*

OpenStudy (anonymous):

OH.... I got -23 for my final answer!

Nnesha (nnesha):

:=)

OpenStudy (anonymous):

Thank you!

Nnesha (nnesha):

my pleasure :=) o^_^o

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