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If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below. 17 23 −17 −23
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first find j(2) substitute x for 2 into j(x) function
So the answer would end up to be C?
how ?? hm
j(2) = ?
(-2x)= \[-2\times2?\]
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yes right j(2) = -2 times 2
Which would = -4
now substitute x for j(2) value into h(x) function
I am confused on this part....
hhaha alright so you need h[j(2)] j(2) =-4 so in other words you need h(-4) now substitute x for -4 into h(x) funtion
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\[\huge\rm h(-4)=5\color{ReD}{x}-3\] replace x for -4 and then sovle!
solve*
OH.... I got -23 for my final answer!
:=)
Thank you!
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my pleasure :=) o^_^o
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