Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball?
H(t) = −16t^2 + 6t + 22
H(t) = −16t^2 + 22t + 6
H(t) = −16t^2 + 28t
H(t) = −16t^2 + 28
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OpenStudy (lochana):
oh this is easy. H(0) must be 6
OpenStudy (lalaland_lauren):
I'm not sure tbh, I'm not very good with all this. Could you explain it to me?
OpenStudy (lochana):
yes
OpenStudy (lochana):
I am assuming 't' is the time and H(t) is the height of the ball for a given 't'. So it says that the ball starts its motion from 6 feet of height .
OpenStudy (lochana):
doesn't matter what the velocity is
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OpenStudy (lochana):
it is clear that initial height is 6
OpenStudy (lochana):
start means t=0
OpenStudy (lochana):
just put 0 for t, and one takes 6 is the answer:)
OpenStudy (lalaland_lauren):
but which of the choices is the answer? because you say six is the answer but it's not clear to me
OpenStudy (lochana):
ah yes. So think about 2nd one
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OpenStudy (lochana):
if put 0 for each 't' , it is something like
H(0) = -16(0)^2 +22(0) + 6
OpenStudy (lochana):
solve it. will get 6
OpenStudy (lalaland_lauren):
OHHHHHHH okay
OpenStudy (lalaland_lauren):
I uderstand it now xD
OpenStudy (lochana):
bye
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