Question

help plz medal and fan Simplify
sin^2 theta /1- cos^2 theta

Answer 1

\[\huge\rm cos^2 \theta + \sin^2 \theta =1 \]you should remember this equation!!

Answer 2

solve for sin^2theta

Answer 3

-cos(2 theta)
2 sin^2(theta)-1

Answer 4

cos^2 theta .. yes ????

Answer 5

what about it ? :=)

Answer 6

is that the answer ????

Answer 7

no

Answer 8

Okay let me try and get it

Answer 9

sure!

Answer 10

sin^2theta +cos^2theta = 1
1-cos^2theta=sin^2theta
so we can write -> sin^2theta/sin^2theta = 1
but the condition is that sin(theta) does not equal 0

Answer 11

sin2theta

Answer 12

Yes ??

Answer 13

that's one of the option....

Answer 14

can u explain how did u get sin2theta

Answer 15

By 1-cos2theta=sin2theta........................... i think

Answer 16

\[\frac{ \sin^2\theta }{\color{ReD}{ 1-\cos^2 }}\] now replace 1-cos^2for sin^2x
bec 1-cos^2x=sin^2x

Answer 17

Omg i dont understand

Answer 18

\[\huge\rm cos^2 \theta + \sin^2 \theta =1 \]
solve for sin^2\[\rm sin^2\theta=1-\cos^2\theta\] you will get sin^2 =1-cos^2 right ?

Answer 19

Yes

Answer 20

okay so if sin^2theta =1-cos^2 you can replace the (1-cos^2) which is at the dneominator with sin^2 theta right ?

Answer 21

\[\huge\rm \frac{ \sin^2\theta }{\color{ReD}{ 1-\cos^2 }}\] replace 1-cos^2for sin^2x
bec \[\huge\rm \color{reD}{ 1-\cos^2x}=\sin^2x \]

Answer 22

so the answer is sin right

Answer 23

\[\frac{ \sin^2 x }{ \color{reD}{\sin^2x}}=?\]

Answer 24

let sin^2x = a
so a/a = ??

Answer 25

a divide by a = ??

Answer 26

0

Answer 27

no never!

Answer 28

there is always invisible one!!

Answer 29

2/2 = ??

Answer 30

1 lol

Answer 31

ye.-.

Answer 32

okay thnks