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OpenStudy (anonymous):
Verify the identity. Show your work.
cos(α - β) - cos(α + β) = 2 sin α sin β
my answer>cos=o
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OpenStudy (anonymous):
Teacher:Use the sum and difference formulas for this
me:wtf you mean
OpenStudy (anonymous):
@misty1212
OpenStudy (sohailiftikhar):
cos(a-b)=cos(a)cos(b)+sin(a)sin(b)
cos(a+b)=cos(a)cos(b)-sin(a)sin(b)
these are the formulas
OpenStudy (anonymous):
woow ok so do i use both of them or what
OpenStudy (sohailiftikhar):
you have both terms cos(a-b) and cos(a+b) so use both
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OpenStudy (sohailiftikhar):
in this problem
OpenStudy (anonymous):
ok so this is a practice question imma gonna be graded on so can you help me plz
OpenStudy (sohailiftikhar):
ok
OpenStudy (anonymous):
2cos(A)cos(B)=2cos(A)cos(B) ok so i got this instead is this right
OpenStudy (anonymous):
@misty
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OpenStudy (sohailiftikhar):
no it's not right
OpenStudy (sohailiftikhar):
ok i'm going to solve it
OpenStudy (sohailiftikhar):
\[\cos(\alpha-\beta)-\cos(\alpha+\beta)=(\cos \alpha \cos \beta +\sin \alpha \sin \beta)-(\cos \alpha \cos \beta -\sin \alpha \sin \beta )\]
OpenStudy (sohailiftikhar):
now \[\cos \alpha \cos \beta +\sin \alpha \sin \beta -\cos \alpha \cos \beta +\sin \alpha \sin \beta =2 \sin \alpha \sin \beta \]
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