Score Number of Students
0 2
1 1
2 3
3 6
4 2
5 3
6 2
Based on the table, what is the mean hockey score?
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OpenStudy (anonymous):
@heretohelpalways
OpenStudy (anonymous):
@Nishant_Garg
OpenStudy (anonymous):
i added them all up i got 19
OpenStudy (anonymous):
mean or average is total observations divided by number of observations or how frequent those observations are
\[mean=\frac{0+1+2+3+4+5+6}{2+1+3+6+2+3+2}\]
OpenStudy (anonymous):
7 over 19? @Nishant_Garg
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OpenStudy (anonymous):
@heretohelpalways
OpenStudy (anonymous):
doesn't look right
OpenStudy (anonymous):
thats why i need help im confused
OpenStudy (anonymous):
what is 1+2+3+4+5+6?
OpenStudy (anonymous):
21
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OpenStudy (anonymous):
so 21/19
OpenStudy (anonymous):
1.2
OpenStudy (anonymous):
?
OpenStudy (anonymous):
@Nishant_Garg
OpenStudy (anonymous):
1.105
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OpenStudy (anonymous):
thats not a choice though....
OpenStudy (anonymous):
@heretohelpalways
OpenStudy (anonymous):
do 0+0+1+2+2+2+3+3+3+3+3+3+4+4+5+5+5+6+6 DIVIDED BY
OpenStudy (anonymous):
Divide that by 19
OpenStudy (anonymous):
to get about 3.15
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OpenStudy (anonymous):
Is that an option?
OpenStudy (anonymous):
@KAKES1967 Are you still there?
OpenStudy (anonymous):
2.14
OpenStudy (anonymous):
these are the options...2.7
2.9
3.2
5.2
OpenStudy (anonymous):
2.7?
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OpenStudy (anonymous):
insteresting, one second
OpenStudy (anonymous):
this is getting confusing
OpenStudy (anonymous):
@nincompoop
OpenStudy (anonymous):
@abb0t
OpenStudy (anonymous):
@ganeshie8
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OpenStudy (anonymous):
@IrishBoy123
OpenStudy (anonymous):
@Smita12
OpenStudy (irishboy123):
you need to weight the scores
so
\(\large \frac{2*0 + 1*1 + 3*2 + ...}{2 + 1 + 3...}\)
OpenStudy (anonymous):
7 over 6
OpenStudy (anonymous):
@IrishBoy123
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OpenStudy (irishboy123):
you need to complete that calculation i started.
i included the first 3 numbers, include the remaining 4 in exactly the same way; and you will get there