Solve 2x2 − 8x = −7.
negative 2 plus or minus square root of 2
negative 2 plus or minus 2 square root of 2
quantity of 2 plus or minus square root of 2 all over 2
2 plus or minus square root of 2 end root over 2
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OpenStudy (anonymous):
correct answer will get medal and fan
OpenStudy (anonymous):
@aaronq @Nnesha
Nnesha (nnesha):
set it equal to zero
Nnesha (nnesha):
then use quadratic\[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] formula
a b and c are \[\large\rm Ax^2+Bx+C=0\]
a=leading coefficient
b=middle term
c=constant term
OpenStudy (anonymous):
a=3,b=−7,c=3
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OpenStudy (anonymous):
@Nnesha
Nnesha (nnesha):
bo
Nnesha (nnesha):
\[2x^2-8x=-7\] first set it equal to zero write it in Ax^2+Bx+C=0 form
add 7 both sides
OpenStudy (anonymous):
so b is correct @Nnesha
Nnesha (nnesha):
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
bo
\(\color{blue}{\text{End of Quote}}\)
correction
no
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Nnesha (nnesha):
add 7 both sides let me know what you get
OpenStudy (anonymous):
4 ± 2√ 2
OpenStudy (anonymous):
but thats not an answer choice @Nnesha
Nnesha (nnesha):
that should be in fraction form
Nnesha (nnesha):
a= ??
there is 2a at the denominator replace a by its value and multiply that with 2
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