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Mathematics 6 Online
OpenStudy (anonymous97):

Use the graph below to answer the question that follows: cosine graph with points at 0, 3 and pi, negative 5 and 2 pi, 3 What are the amplitude, period, and midline of the function? Amplitude: 4; period: 2π; midline: y = −1 Amplitude: 8; period: 2π; midline: y = 1 Amplitude: 8; period: π; midline: y = −1 Amplitude: 4; period: π; midline: y = 1

OpenStudy (anonymous97):

OpenStudy (anonymous):

you have a graph, so all the questions get answered from your eyeballs, not from an equation or some kind of algebra

OpenStudy (anonymous):

the period is the length over which the function makes one complete cycle. take a look and see where it is at its peak, and the next peak. the length of of that interval (on the x axis) is the period

OpenStudy (anonymous):

the amplitude is half the distance from the lowest most point on the graph to the upper most point

OpenStudy (anonymous97):

thank you so much

OpenStudy (anonymous):

yw if you would like me to check your answer let me know

OpenStudy (anonymous97):

amplitude is 4 correct?

OpenStudy (anonymous):

yes from -5 to 3 is 8 units, half of that is 4

OpenStudy (anonymous97):

so for period its the highest arc to the lowest arc

OpenStudy (anonymous97):

how do i find midline?

OpenStudy (anonymous):

it is half way between -5 and 3

OpenStudy (anonymous):

as the name suggests it is the horizontal line that is "midway" between the max and the min

OpenStudy (anonymous):

and no, the period is not from the highest to lowest

OpenStudy (anonymous97):

okay so the answer is A?

OpenStudy (anonymous97):

cause the midline is -1

OpenStudy (anonymous):

yes, a rare A

OpenStudy (anonymous97):

thank you i appreciate it

OpenStudy (anonymous):

yw

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