Question

Write the quadratic function in vertex form.

y = x2 - 2x + 5

Answer 1

first coordinate of the vertex of \\(y=ax^2+bx+c\) is always
\[-\frac{b}{2a}\]

Answer 2

second coordinate of the vertex is what you get for \(y\) when you replace \(x\) by the first coordinate

Answer 3

once you have the vertex \((h,k)\) then vertex form is
\[y=a(x-h)^2+k\] in your case \(a=1,b=-2\)

Answer 4

i can check your answer if you like

Answer 5

y=(x+1)^2-4?

Answer 6

oh no

Answer 7

your signs are messed up

Answer 8

\[-\frac{b}{2a}=-\frac{-2}{2\times (-1)}=1\]

Answer 9

if you replace \(x\) by \(1\) you get \(4\) not \(-4\)

Answer 10

so
\[y=(x-1)^2+4\]

Answer 11

Thanks!

Answer 12

yw