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Choose the correct simplification of the expression the quantity a to the 2nd power over b to the 3rd power all raised to the 4th power. a to the 6th power over b to the 7th power b12 a8b15 the quantity a to the 8th power over b to the 12th power
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@jdoe0001
is it d?\[\frac{ a^8 }{ b^12 }\]
b^12, so like an exponent of 12, not 1...
hmm what makes you think is d anyway?
idk, I originally thought it was a, but idk
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\(\bf (a^n)^m\implies a^{n\cdot m}\quad thus \\ \quad \\ \left( \cfrac{a^2}{b^3} \right)^{\color{brown}{ 4}}\implies \left( \cfrac{a^{2\cdot {\color{brown}{ 4}}}}{b^{3\cdot {\color{brown}{ 4}}}} \right)\)
so...should be obvous I'd think
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