A right triangle has base (x - 6) units and height (6x - 12) units. Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points) Part B: What is the area of the triangle? (3 points) Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)
correlation coefficient is 1 slope is 5/10 which reduces to 1/2 not sure about the 3rd one
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@HootHoot help plz
do you know the Pythagorean Theorem? (it's both famous and useful for this problem)
OK ILL GET MY BRO ON IT
kk
ok i sent the question to em he is working on it
I think it has to do with A^2 + B^2 = C^2 where C^2 is your hypotenuse. (x-6)^2 + (6x - 12)^2 = c^2.ok he belives it like this
whats epic
i tinhk hoot hoot is correct
do your foiling and stuff
f= first, o=outside, i=inside, l=lasts
we know that
it shouldnt be that much harder from here
(6x-13)^2 = (6x-12)(6x-12)
do the same thing for the base
write it out like Part a... Part b... and part c...
@jcoury
@jcoury
Part A (6x-12)^2 + (x - 6)^2 (36x^2 - 144x +144) + (x^2 - 12x + 36)
\[37^{2}-156x+180\]
Part B: The area A of a triangle is A=(1/2)bh where b is base and h is height. Refer to diagram above A=(1/2)(x-6)(6x-12) simplify by taking 1/2 of the height h getting (3x-6) now multiply (x-6)(3x-6) getting: 3x^2 - 24x + 36 sq units
Part C. Just show that the multiplication of two polynomials (x-6)(3x-6) results in a polynomial 3x^2 - 24x + 36 as a result of the distributive process and combing of similar terms.
nice XD
XD lol
@OregonDuck can u help me real quick
help with part c. sure
tag me
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