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No direct answers please. Just need to know how to solve it.
\(\Large 4x-\frac{6}{y}=15\) \(\Large 4x-\frac{6}{2}=15\) Did you replace y with 2 already?
Yes
How do i do it
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\(\Large 4x-\frac{6}{2}=15\) Let's get rid of the simple fractions. What is 6/2 ?
3!!!!!!!!!!!
Good. That means \(\Large 4x-3=15\)
Now, combine like terms.
1 and 15?
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-3 and 15 are like terms. Move -3 to the other side by adding 3 to both sides of the equation.
Can you do that?
18 and 6
\(\large 4x−3+3=15+3\) \(\large 4x=18\) What is the next step?
Sorry I am kind of confused because I am tired and have been working all day.
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4=18
wait sorry
You divide both sides by 4 to leave x alone. \(\large 4x=18\) \(\LARGE\frac{4x}{4}=\frac{18}{4}\)
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