Question

please help will fan and medal.
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Answer 1

@pooja195

Answer 2

@welshfella

Answer 3

there are 3 zeros:- -1 duplicity 2 and 1
so in factor form it is
(x+1)^2(x-1)

Answer 4

I am confused.

Answer 5

if you look at the graph you see that at x = -1 the graph touches the x-axis and the it pass through the point where x = 1

these are called the zeros of the function
its a cubic function so it has 3 zeros;- 2 at x = -1 and 1 at x = 1
if we write
(x + 1)^2(x - 1) = 0

we get x -1 = 0 or (x +1)^2 = 0

giving x = 1 and x = -1 (twice)

Answer 6

so iy you expand (x - 1)(x + 1)(x + 1) you'll get the correct function

Answer 7

do it by multiplying the last 2 factors first - giving x^2 + 2x + 1

so we have

(x - 1)(x^2 + 2x+ 1) = ?

Answer 8

\[x^3+x^2−x−1=?\]

Answer 9

yep

Answer 10

Thank you!

Answer 11

welcome