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The function I'm looking for I'll call \(f(n)\). It obeys this relationship to the zeta function: \[\zeta(s) = \sum_{n=1}^\infty \frac{1}{n^s}\] Here's the relationship: \[[\zeta(s)]^i = \sum_{n=1}^\infty \frac{f(n)}{n^s}\]
This is one sort of generalization of the Mobius function \(\mu(n)\) which obeys this relationship for anyone who's interested or curious why I'm interested in this. :P \[[\zeta(s)]^{-1} = \sum_{n=1}^\infty \frac{\mu(n)}{n^s}\]
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