Question

1/7(B+35)3 linear equations

Answer 1

@Leong

Answer 2

@ganeshie8

Answer 3

@LynFran

Answer 4

@Leong

Answer 5

@mathway

Answer 6

@izuru

Answer 7

@mathstudent55

Answer 8

can you help me @RunawayGalaxy

Answer 9

Well you're not being too clear in the question you're asking here, do you want to solve for B ?

Answer 10

yes

Answer 11

I don't understand what the problem is. There is no equal sign, so this is not an equation. what do you need to do?

Answer 12

ohh so sorry =3

Answer 13

Ok. Let me write it again.

Answer 14

ok

Answer 15

Solve for B:

\(\large \dfrac{1}{7}(B + 35) = 3\)

Answer 16

Is that the problem?

Answer 17

yes

Answer 18

Ok. You have a multiplication of 1/7 on the left side that we need to get rid of.
To get rid of a multiplication, you multiply by its reciprocal.
The reciprocal of 1/7 is 7, so we multiply both sides by 7.
Can you do that and show what you get?

Answer 19

\(\large 7 \times \dfrac{1}{7}(B + 35) = 7 \times 3\)

What do you get?

Answer 20

7b and 245

Answer 21

No.
On the let side, what is 7 * 1/7?
The whole idea of multiplying both sides by 7 is to get rid of 1/7 on the left side.
What is 7 * 1/7?

Answer 22

1