Question

Solve X.
A triangle ABC, with point D on line AB and point E on line AC. Point F is the intersection of line DC and EB.
Angle ACD = 10
Angle DCB = 70
Angle EBC = 60
Angle EAD = 20
Angle EDC = x

These r the only information given.
Many Thanks!

Answer 1

Here's a graphic

Answer 2

yes wolfi done this already by telling the graph bro

Answer 3

there is nothing to tell now

Answer 4

Angle ADC = 180 -20 -10 = 150 Degrees
Angle CDB = 30 Degrees
Angle B = 180 -20 -(10+70) = 80 Degrees
Angle EBA = 20 Degrees
Angle EFD = 360 -140 -150-20 = 50 Degrees = Angle CFB

Well maybe I'll give this a rest now

Answer 5

@imqwerty but x is Angle EDC, not Angle ADC

Answer 6

oops :D sry i'll correct it

Answer 7

thank you!

Answer 8

@imqwerty i got everything you guys get, but i couldnt get EDC, that's why i'm asking it here. :P

Answer 9

Seems this is still unsolved.
Let's see if this helps.
Triangle ACB is isosceles side AC = side AB
Triangle AEB is isosceles side AE = side EB
Any ideas anyone?

Answer 10

Haven't given up yet.
I redrew the graphic trying to be as accurate as possible.
(All the angles were drawn as closely as possible to their posted values.)

Answer 11

\[\href{
https:///www.duckware.com/tech/worldshardesteasygeometryproblem.html
}{\Huge \cal Click ~Here!!}\]

Answer 12

Thanks for the answer.

Answer 13

Yw!

Answer 14

But I recommend you not to read that answer straight away. Have sometime to try it yourself.

Answer 15

amilspan I've worked on it long enough. I drew both of the graphics posted here.

Answer 16

thanks guys! Really appreciate the effort.:)))