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Mathematics 17 Online
OpenStudy (anonymous):

need help factoring (completely) x^2-5x+6

OpenStudy (anonymous):

?

OpenStudy (triciaal):

this is in the form ax^2 + bx + c to find factors set = 0 when (x-h) is a factor the remainder = 0 h is a number here are the steps to factor: identify your a, b, c find a*c list the factors of a*c including the signs find factors of a*c that will add up to b rewrite the function to "split" b into 2 components regroup the terms and find the common factors use the distributive property

OpenStudy (triciaal):

can you try or do you want me to do this with you ?

OpenStudy (anonymous):

a is 1 b is5 and c is 6

OpenStudy (anonymous):

i know that you can do it this way (x ) (x )

OpenStudy (anonymous):

but i get confused on the middle part (something about the product of the first and last gives the middle...?

OpenStudy (anonymous):

u still ther?

OpenStudy (triciaal):

check your b

OpenStudy (anonymous):

oh its -5

OpenStudy (triciaal):

what is the product of a*c?

OpenStudy (anonymous):

6

OpenStudy (triciaal):

what are the factors of 6 then choose the ones that will add up to -5?

OpenStudy (anonymous):

-2 and -3

OpenStudy (triciaal):

good now rewrite the original with -2 and -3 instead of just -5

OpenStudy (anonymous):

so the answer would be (x-2) (x-3)

OpenStudy (anonymous):

oh x^2-2x-3x+6

OpenStudy (triciaal):

yes but I was showing all the steps to get there

OpenStudy (anonymous):

oh ok continue

OpenStudy (triciaal):

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