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OpenStudy (anonymous):
?
OpenStudy (triciaal):
this is in the form ax^2 + bx + c
to find factors set = 0
when (x-h) is a factor the remainder = 0 h is a number
here are the steps to factor:
identify your a, b, c
find a*c list the factors of a*c including the signs
find factors of a*c that will add up to b
rewrite the function to "split" b into 2 components
regroup the terms and find the common factors
use the distributive property
OpenStudy (triciaal):
can you try or do you want me to do this with you ?
OpenStudy (anonymous):
a is 1 b is5 and c is 6
OpenStudy (anonymous):
i know that you can do it this way (x ) (x )
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OpenStudy (anonymous):
but i get confused on the middle part (something about the product of the first and last gives the middle...?
OpenStudy (anonymous):
u still ther?
OpenStudy (triciaal):
check your b
OpenStudy (anonymous):
oh its -5
OpenStudy (triciaal):
what is the product of a*c?
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OpenStudy (anonymous):
6
OpenStudy (triciaal):
what are the factors of 6 then choose the ones that will add up to -5?
OpenStudy (anonymous):
-2 and -3
OpenStudy (triciaal):
good
now rewrite the original with -2 and -3 instead of just -5
OpenStudy (anonymous):
so the answer would be (x-2) (x-3)
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