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Mathematics 7 Online
OpenStudy (anonymous):

chloe randomly selects a card from a standard deck of cards. what is the probability she selects an ace ??

OpenStudy (anonymous):

wats that ??

jimthompson5910 (jim_thompson5910):

how many aces are there in the deck?

OpenStudy (anonymous):

it dosent say

jimthompson5910 (jim_thompson5910):

are you familiar with a deck of cards and how many aces there are?

OpenStudy (anonymous):

4 aces

jimthompson5910 (jim_thompson5910):

yep, out of how many total?

OpenStudy (anonymous):

@jim_thompson5910 how many total what ?? cards if 56 right

jimthompson5910 (jim_thompson5910):

52 actually

jimthompson5910 (jim_thompson5910):

13 cards per suit * 4 suits = 52 total

jimthompson5910 (jim_thompson5910):

probability of picking an ace = (# of aces)/(# of cards total)

jimthompson5910 (jim_thompson5910):

make sure to reduce the fraction as much as possible

OpenStudy (anonymous):

so i do 4/52 reduce that

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

1/13

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

So you can think of it like this: pick any suit you want. What is the probability of getting an ace for that suit only? It's 1/13 since there's 1 ace out of 13 cards in that suit

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