Find the product of 21 and (6.3 • 10^-4). 0.1323 • 10^-1 1.323 • 10^-3 1.323 • 10^-2 1.323 • 10^2
first multiply 21 * 6.3 and write it in the exponent form post you answer here
132.3
can you write that in 'exponent form ? like 1.56 * 10^2
Is it 132.3 * 10^0?
that is one way to write it can you write it as 1.323 * 10^?
is it possible, you're asking?
no - it is possible can you do it - what is the value of ? so that 132.3 is the same as 1.323 *10^?
I know that you have to move the decimal over two spaces to the left by dividing it by 100. That IS correct, right? XD
yes 132.3= 1.323*100 = 1.323 *10^? what is the value of ? in the above?
I have no clue. 1.323*100 is 132.3 but that's what we started with...
the point of the exercise is to be able to express numbers in exponent form (or sometimes called scientific notation) you can see maybe that (for example) 1101 = 110.1 *10^1 1101 = 11.01 * 10^2 1101 = 1.101 * 10^3 1101 = .1101 * 10 ^4 SO using the same idea can you look at 132.3= 1.323*100 = 1.323 *10^?
is it... 1.323 • 10^-3
is it... 1.323 • 10^-3
132.3= 1.323*100 we are multiplying by 100 how would you write 100 = 10^?
eh... I dont know
Well I'm afaid you are probably not ready to tackle questions like this then. The key point is that we can move the decimal point where we want - as LONG AS we multiply by 10^? to compensate. BUT you must know that 10^0 =1 10^1 = 10 10^2 = 100 10^3 = 1000 etc.
Oh! Oh that makes sense
how would you write 100 = 10^?
100 would be 10^2
OK so lets go back toi the original question 21 *6.3 • 10^-4 you worked out was the same as 132.3 *10^4 which is the same as 1.323 *10^2 * 10^-4 so what happens when you multiply 2 numbers with exponents? 10^2 * 10^-4 = 10 ^?
When you multiply 2 numbers with exponents dont you add the exponents and if the bases are the same then you keep them as that number? So this would be 10^-2?
excellent - so you have your answer now
Ah! Thank you so much
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