Question

A right triangle has base (x - 5) units and height (4x - 10) units.
Part A: What is the square of the length of the hypotenuse of the triangle?

Answer 1

"square of the length of the hypotenunse" = (base)^2 + (height)^2

Answer 2

(x-5)^2 + (4x -10)^2

Answer 3

@Vocaloid

Answer 4

correct

Answer 5

Solve what you've written out.

Answer 6

oh, well, I guess you could try expanding it

(x-5)^2 = (x-5)(x-5) = ?
(4x-10)^2 = (4x-10)(4x-10) = ?

Answer 7

x^2-10x+25

x^2 -20x+100

Answer 8

first one looks good

check the second one again

Answer 9

oh 4x sorry

Answer 10

nope, not quite...

(4x)*(4x) = ?

Answer 11

no i did x instead of 4x

Answer 12

let's start again

(4x-10)^2 = (4x-10)(4x-10) = ?

Answer 13

remember foil? first we multiply the first terms in each parentheses

(4x)*(4x) = ?

Answer 14

16x^2-80x+100

Answer 15

yup! that looks much better

now we have:

x^2-10x+25
16x^2-80x+100

Answer 16

Okay

Answer 17

now we add everything together

combine like terms:

x^2 + 16x^2 = ?

Answer 18

16x^2-90x+125 i forgot if you add the exponents or not

Answer 19

17x^2-90x+125 sorry

Answer 20

@Vocaloid is that it?

Answer 21

yup! good job

Answer 22

That doesnt seem like the right answer to the question but okay