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Mathematics 8 Online
OpenStudy (anonymous):

Given that PHT is a right triangle HY and is an altitude, what is the missing justification in the proof that(PH)2 +(HT)=(PT)2 ? http://media.apexlearning.com/Images/201306/28/eeb89b21-59b3-4f42-945a-8a99fa28ed69.jpg http://media.apexlearning.com/Images/201310/23/fcf6f216-c94a-423d-8e75-54042c79988d.jpg A. Corresponding sides of congruent triangles are proportional. B. Corresponding sides of congruent triangles are congruent. C. Corresponding sides of similar triangles are congruent. D. Corresponding sides of similar triangles are proportional.

OpenStudy (anonymous):

MEDAL AND FAN

OpenStudy (amilapsn):

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OpenStudy (anonymous):

how does that help ive been looking at that my other screen for the last ten minutes

OpenStudy (amilapsn):

Please check if there's an typo in your question...(What you've typed)

OpenStudy (amilapsn):

It should be \(PH^2+HT^2=PT^2\) right?

OpenStudy (anonymous):

yea

OpenStudy (amilapsn):

So we have to answer the question why is \(\sf\frac{HT}{PT}=\frac{YT}{HT}\)ok?

OpenStudy (anonymous):

yep

OpenStudy (amilapsn):

In the earlier step it has been proven that \(\sf\Delta PHT \text{ is similar to } \Delta HYT\). What are they, triangles or angles?

OpenStudy (anonymous):

triangles

OpenStudy (amilapsn):

Very well. are they similar or congruent?

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