Pre-calculus 12 question!
well, the height of the rectangle is given by the equation y = 9 - x^2 and the width is 2x
Ok
so area = ?
I know how to get the area, but how do you know the height?
@Vocaloid
well, think of it this way: on the x-y coordinate plane, the x value tells you how far to the right or left to go, and the y-value tells you how far up or down to go, correct? since we want the height of the rectangle, it naturally follows that we want the y value
yes correct
so, we're given the equation y = 9 - x^2, so that's our height
but the height of the rectangle is far smaller than the original prabola
nope, not necessarily, remember that x is not a fixed value if we make x something super small, like 0.00001, then the height of the rectangle is almost the height of the parabola the point is that x changes
ok I got this, and about the width, it looks like 4x to me. How is it 2x?
well, think of it this way. let's try splitting the rectangle in half down the y-axis, like this: |dw:1440359170630:dw|
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