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Mathematics 9 Online
OpenStudy (korosh23):

Pre-calculus 12 question!

OpenStudy (korosh23):

Vocaloid (vocaloid):

well, the height of the rectangle is given by the equation y = 9 - x^2 and the width is 2x

OpenStudy (korosh23):

Ok

Vocaloid (vocaloid):

so area = ?

OpenStudy (korosh23):

I know how to get the area, but how do you know the height?

OpenStudy (korosh23):

@Vocaloid

Vocaloid (vocaloid):

well, think of it this way: on the x-y coordinate plane, the x value tells you how far to the right or left to go, and the y-value tells you how far up or down to go, correct? since we want the height of the rectangle, it naturally follows that we want the y value

OpenStudy (korosh23):

yes correct

Vocaloid (vocaloid):

so, we're given the equation y = 9 - x^2, so that's our height

OpenStudy (korosh23):

but the height of the rectangle is far smaller than the original prabola

Vocaloid (vocaloid):

nope, not necessarily, remember that x is not a fixed value if we make x something super small, like 0.00001, then the height of the rectangle is almost the height of the parabola the point is that x changes

OpenStudy (korosh23):

ok I got this, and about the width, it looks like 4x to me. How is it 2x?

Vocaloid (vocaloid):

well, think of it this way. let's try splitting the rectangle in half down the y-axis, like this: |dw:1440359170630:dw|

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