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first find the derivative of this function
can you do that?
implicit differentiation. Treat y as a function of x.
Yes I got 6x^2-3xy'(x)+3y^2y'(x)-3y
= 0
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looks good
now its just algebra
Plugging in the points?
make y' the subject then plug in the points
y'(x)
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do you know what I mean ?
Yeah like set everything equal to y'(x) right?
yea - like solving for y'(x)
Okay I got -6x^2+3x/-3x3y^2=y'(x)
now its just a matter of plugging in the given values of x and y
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There was an error I think my formula is wrong
yes i got a different result foe y'(x)
I got -18
i get -11/7
i might have it wrong as I'm getting tired.
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Let me try it again
Oh wait yeah I see where I went wrong I plugged in the wrong points but I got -11/7 now
Thank you!!!!
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