Memory refresher..
Subtract 7-(-5+6i)-(-1-i)
be careful with the signs remember that - * + = - and -*- = + when you are distributing the negative over the 2 parentheses
Im assuming that your talking about the minus sign between the two parenthesis. The part that has me a bit stuck is the 7-. I know how to distribute the negative sign to others.
Ok, you got that \(i=\sqrt{-1}\) , right?
or, is it just variable/
Yes. This is complex numbers.
the first negative is distributed about the first parentheses in the usual way
The one behind the 7?
I read that:P
keep real part together and terms with " i " together this is all what you need to remember :)
the one after the 7 Yes
i wrote art @SolomonZelman :P
despite that it's my 3rd language, I got good at it lately:)
in any case,
7(5-6i)-(-1-i) Now I times 7 to the first parenthesis and distribute the negative to the second correct?
if you like you can treat the - before the parentheses as -1 - so multiply everything in parentheses by -1
36-41i
7 - (-5 + 6i) = 7 + 5 - 6i
distributing the negative over - 5 + 6i gives + 5 - 6i
- you are not multiplying the -5 + 6i bt multiplying it by -1
* not multiplying the -5 + 6i by 7 I meant to say
Why not? I just get rid of the parenthesis by distributing the negative?
I got 13-5i
yes and the 7 isn't touched - it stays put
7 + 5 - 6i - (-1 - i) = 12 - 6t + 1 + i = 13 - 5i
right
okay.
good
actually, doesn't matter whether i is a variable or imaginary number, you get the same result.
well, not the same value, but a result that is recorded in the same way.
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