Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Use the table below to find g(-5). http://prntscr.com/88pg75 Write a function rule based on the table below. http://prntscr.com/88pgio

OpenStudy (welshfella):

for the first one just read off the values of g(x) corresponding to x = -5

OpenStudy (anonymous):

i honestly dont know what to do exactly

OpenStudy (welshfella):

llok at the column heading x and find -5 then read off the value next to it

OpenStudy (anonymous):

so -2 and 0

OpenStudy (welshfella):

this gives you the value of g(x) when x = -5 it is written as g(-5)

OpenStudy (welshfella):

No just -2

OpenStudy (anonymous):

oh ok so the final answer would be -2

OpenStudy (welshfella):

for the first question Yes

OpenStudy (welshfella):

For the second question the function will be of the form f(x) = nx + 5 because when x = 0, f(x) = 5 ( check the table) f(x) = 0*n + 5 = 5 (0 times n = 0)

OpenStudy (welshfella):

now need to find the value of n we see from the table that f(x) = 8 when x = 1 so 8 = n + 5 can you solve this for n?

OpenStudy (welshfella):

what number added to 5 gives you 8?

OpenStudy (anonymous):

3

OpenStudy (welshfella):

right so it looks like the function is 3x + 5 lets check it out with the third row of the table when x = 2 , f(x) = 11 so if we plug these values into f(x) = 3x + 5 we get 11 = 3* 2 + 5 is that correct? does 3*2 + 5 = 11?

OpenStudy (anonymous):

This is the answer key f(x)=x+5 f(x)=8x f(x)=3x+5 f(x)=5x-3

OpenStudy (welshfella):

so which one is correct?

OpenStudy (anonymous):

a

OpenStudy (welshfella):

NO check out my last 2 posts

OpenStudy (anonymous):

ohhhhh my mistake its c

OpenStudy (welshfella):

correct

OpenStudy (anonymous):

can you help me with one last question?

OpenStudy (welshfella):

yes bu t plz post it separately

OpenStudy (anonymous):

ok np

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!