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if the point (2/3, y) is on the unit circle, what is y? A.) 2/3 B.) 1/3 C.) √5/3 D.) 4/9
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Do you know what algebraic equation describes the unit circle?
no i don't
|dw:1440627793246:dw|
Ok, the unit circle is described by the equation\[x^2 + y^2 = 1\]
its that man Pythagoras again..
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So, if x = 2/3, then we can compute\[y^2 = 1 - x^2 \implies y^2 = 1 - \left(\frac{2}{3}\right)^2 \]
Yes, Pythagoras, he gets around.
haha okay I got it now ^_^ thank you guys so much!
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