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\[2x^2-5x+2=(x-3)(x-2)+3x\]
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@jdoe0001 Help again?
The first thing you need to do is multiply out the parenthesis on the right side.
I know... I already got it down to \(x^2-3x-4=0\)
wait... I don't need help
lol
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sorry XD
Well good then.
To see what is in front of one's nose needs a constant struggle. ~~ George Orwell, "In Front of Your Nose" ~~
That's easily factorable and you get (x-4)(x+1) so your zeros are 4 and -1
well... (x-4)(x+1)=0
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