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OpenStudy (bloomlocke367):
\[2x^2-5x+2=(x-3)(x-2)+3x\]
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OpenStudy (bloomlocke367):
@jdoe0001 Help again?
OpenStudy (marihelenh):
The first thing you need to do is multiply out the parenthesis on the right side.
OpenStudy (bloomlocke367):
I know... I already got it down to \(x^2-3x-4=0\)
OpenStudy (bloomlocke367):
wait... I don't need help
OpenStudy (bloomlocke367):
lol
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OpenStudy (bloomlocke367):
sorry XD
OpenStudy (marihelenh):
Well good then.
OpenStudy (jdoe0001):
To see what is in front of one's nose needs a constant struggle. ~~ George Orwell, "In Front of Your Nose" ~~
OpenStudy (bloomlocke367):
That's easily factorable and you get (x-4)(x+1) so your zeros are 4 and -1
OpenStudy (bloomlocke367):
well... (x-4)(x+1)=0
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