Question

\[2x^2-5x+2=(x-3)(x-2)+3x\]

Answer 1

@jdoe0001 Help again?

Answer 2

The first thing you need to do is multiply out the parenthesis on the right side.

Answer 3

I know... I already got it down to \(x^2-3x-4=0\)

Answer 4

wait... I don't need help

Answer 5

lol

Answer 6

sorry XD

Answer 7

Well good then.

Answer 8

To see what is in front of one's nose needs a constant struggle.

~~ George Orwell, "In Front of Your Nose" ~~

Answer 9

That's easily factorable and you get (x-4)(x+1) so your zeros are 4 and -1

Answer 10

well... (x-4)(x+1)=0