Question

Hello! Can someone please help me work through this quadratic equation which must be solved through completing the square?:
x^2+3+4 = 0

Answer 1

So far I have moved the constant to the RHS
x^2 + 3 + ___ = -4 + ___

Answer 2

What I'm confused on is the number which will fill the blank space. It should be 2.25 but this would make factoring difficult.

Answer 3

Think hard on this: \((a+b)^{2} = a^{2} + 2ab + b^{2}\)

Don't use decimals.

(3/2)^2 = 9/4

It will NEVER make factoring difficult. You are Completing the square. It is, by design, easy to factor after that. The factoing will always be \((a+b)^{2}\) - every time.

Answer 4

Oh, I see now. So it will be (x + 3)^2 and then I will add 9/4 to 4. Thank you!!