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Mathematics 20 Online
OpenStudy (destinyyyy):

What type of solution is this?

OpenStudy (destinyyyy):

Compute the discriminant. x^2-6x-5=0

OpenStudy (destinyyyy):

Answer-> 56

OpenStudy (destinyyyy):

I know if the answer is a negative it is no solution. And if it equals 0 it is exactly one solution.

OpenStudy (destinyyyy):

Is this one an infinite number of real solutions? two unequal real solutions? two imaginary solutions?

OpenStudy (chillout):

Two unequal real solutions. Let Δ be the discriminant. If Δ<0, it has complex solutions. if Δ=0, it has one real solution. if Δ>0, it has 2 real unequal solutions.

OpenStudy (destinyyyy):

Thank you.. For <0 I dont have that as an option

OpenStudy (destinyyyy):

infinite number of real solutions two unequal real solutions two imaginary solutions one real solution

OpenStudy (destinyyyy):

The one im on now has -20 as the answer

OpenStudy (destinyyyy):

Its two imaginary solutions.. But what does the number have to be for it to be infinite number of real numbers?

OpenStudy (destinyyyy):

@Nnesha

OpenStudy (dinamix):

u find 2 solution for this eqution ax^2+bx+c when u c is negative and a is positive

OpenStudy (anonymous):

The graph of a quadratic function is a parabola. It is impossible for there to be an infinite number of solutions, i.e. an infinite number of x-intercepts.

OpenStudy (destinyyyy):

Okay.. So the correct answers are two unequal real solutions example--> 56 Two imaginary example --> -20 One real solution example--> 0

OpenStudy (destinyyyy):

Thank for everyone's help

OpenStudy (anonymous):

You're welcome

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