What type of solution is this?
Compute the discriminant. x^2-6x-5=0
Answer-> 56
I know if the answer is a negative it is no solution. And if it equals 0 it is exactly one solution.
Is this one an infinite number of real solutions? two unequal real solutions? two imaginary solutions?
Two unequal real solutions. Let Δ be the discriminant. If Δ<0, it has complex solutions. if Δ=0, it has one real solution. if Δ>0, it has 2 real unequal solutions.
Thank you.. For <0 I dont have that as an option
infinite number of real solutions two unequal real solutions two imaginary solutions one real solution
The one im on now has -20 as the answer
Its two imaginary solutions.. But what does the number have to be for it to be infinite number of real numbers?
@Nnesha
u find 2 solution for this eqution ax^2+bx+c when u c is negative and a is positive
The graph of a quadratic function is a parabola. It is impossible for there to be an infinite number of solutions, i.e. an infinite number of x-intercepts.
Okay.. So the correct answers are two unequal real solutions example--> 56 Two imaginary example --> -20 One real solution example--> 0
Thank for everyone's help
You're welcome
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