Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

can someone give me a algebra function that equals to 13?

OpenStudy (anonymous):

idk why but well our math teacher gave us that homework and i have no idea where to start.

OpenStudy (anonymous):

f(x) = 13 should do the trick

OpenStudy (anonymous):

well we are supposed to make a function problem for others to solve it...

OpenStudy (anonymous):

so you want an expression with a variable?

OpenStudy (anonymous):

and we are learning pretty advanced math, and it could be actually any algebra problem i think...

OpenStudy (anonymous):

i hope...

OpenStudy (anonymous):

maybe you are supposed to say "let \(f(x)=2x+1\) solve \(f(x)=13\)" maybe

OpenStudy (anonymous):

yeah something like that but more complicated... and u could be asking for y inter, roots, anything

OpenStudy (loganh):

sorry

OpenStudy (anonymous):

um... more complicated... the teacher example is like \[((\sqrt{5})^{2})^{2})-(-3)^0+2!+\frac{ 28 }{ 4 }\]

OpenStudy (anonymous):

for one of her numbers

OpenStudy (anonymous):

any ideas?

OpenStudy (anonymous):

well it is suppsoed to be a review of algebra honors i took last year and since we have the same teacher for 8th geo so she decided to give us this thing

OpenStudy (anonymous):

and i need to make different equations for 13, 4, 2, 0, 4, 0, 2, 2 they have to be different equations idk why.

OpenStudy (anonymous):

I'm confused. Are you looking for a function whose value is 13 at some point? Or are you looking for a PEMDAS style problem that gives 13 as the answer?

OpenStudy (anonymous):

it is a non-word problem relating to algebra that is hard to solve.

OpenStudy (anonymous):

where do the y-intercept/roots come in? The example above doesn't even have a variable. Can you post the exact question you got, maybe that will make it easier to see what it's asking for.

OpenStudy (anonymous):

well... the problem is that i am supposed to make the question. and that equation up there is one of the teacher's examples.

OpenStudy (anonymous):

OpenStudy (anonymous):

this is how the teacher did it

OpenStudy (anonymous):

and so i have me age and bla bla bla bla bla so now i need to make problems out of them

OpenStudy (anonymous):

ok. I see

OpenStudy (anonymous):

I never would have understood what you were after without seeing that

OpenStudy (anonymous):

:P

OpenStudy (anonymous):

sorry i never noticed that i didnt attach the file :|

OpenStudy (anonymous):

any ideas?

OpenStudy (anonymous):

It's hard for someone else to make these up, because we don't really know what you've covered. I don't think they have to be too complex. 2 of them are research style questions and 2 are order of operations type. Maybe do one where you ask for a discriminant of a quadratic equation. Or one that requires some combining of exponents

OpenStudy (anonymous):

she has one that says number of roots. You can probably do something like sum or product of roots. Or make up a system of equations and have one of the answers be the product of the coordinates.

OpenStudy (anonymous):

well that is basicially what we've covered. ,ake it pretty hard please :) well i'm not the one doing it :P

OpenStudy (anonymous):

I wish I could help, Im not very good at math

OpenStudy (anonymous):

:|

OpenStudy (anonymous):

@Leong

OpenStudy (anonymous):

you can... basically just based on her data and makes yours, please check by actually testing and doing it out, not just randomly write it :)

OpenStudy (anonymous):

yea but i need help making mine cz the numbers are different

OpenStudy (anonymous):

OpenStudy (anonymous):

okay okay :3 I'll help you :3

OpenStudy (anonymous):

fhank u!!!!!!!

OpenStudy (anonymous):

thank*

OpenStudy (anonymous):

hey wait let me close this and make another one it takes too long to bump and the replies are too long too

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!