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Mathematics 21 Online
OpenStudy (anonymous):

Help with equation/scenario

OpenStudy (anonymous):

@Nnesha hey can you confirm my answer form ? I got like 3.989 so I'm going with that. I did it by hand so I just want someone to check.

Nnesha (nnesha):

x is an exponent ?

Nnesha (nnesha):

can you please explain or show ur work plz how did you get that answer ? :=)

Nnesha (nnesha):

what was ur first step ?

Nnesha (nnesha):

hey?? :(

OpenStudy (anonymous):

hey sorry afk again. this is what I did (30000=1.18^x * 15 30000=1.18^x * 500) I used scalar multiplying

OpenStudy (anonymous):

@Nnesha

OpenStudy (anonymous):

my book has a whole section on that in this lesson so I thought that was what I do but idk

Nnesha (nnesha):

i don't know why or how you separated de 15 and 5000\[\huge\rm 30000=15500(1.18)^x\] you need to get rid of the 15500 so you can take ln both sides

Nnesha (nnesha):

divide both sides by 15500 and then take natural log

OpenStudy (anonymous):

okay so 30000 / 15500 is 1.9354 and then just 1.18^x I think

OpenStudy (anonymous):

Sorry if I'm not doing this right. Really trying though

Nnesha (nnesha):

yes right \[\huge\rm 1.935=(1.18)^x\] now take natural log both sides

OpenStudy (anonymous):

isn't natural log just log10? I think someone told me that

Nnesha (nnesha):

ln is basically same as log same rules applies for both but ln has base e and and log_!0

Nnesha (nnesha):

log_10

OpenStudy (anonymous):

I'm sorry can you show me how to set it up?

Nnesha (nnesha):

sure btw you can take ln or log you will get the same answer if you take `ln` \[\huge\rm \color{ReD}{ln} 1.935=\color{red}{ln}(1.18)^x\] or `log` \[\huge\rm \color{ReD}{log} 1.935=\color{red}{log }(1.18)^x\]

Nnesha (nnesha):

now apply the power rule \[\large\rm log_b x^y = y \log_b x\]

Nnesha (nnesha):

move the x exponent at front of log or ln

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