Mathematics
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OpenStudy (anonymous):
Linear equation
A= x + y + z/3 solve for y
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OpenStudy (anonymous):
I got the answer y = 3A-x-z but only cause i followed an example so im kind of confused.
OpenStudy (anonymous):
same here
OpenStudy (rizags):
thats not the right answer
OpenStudy (rizags):
first move all varibales to one side, leaving y alone
OpenStudy (anonymous):
On the answer sheet it said it was lol but my teacher said it could be more than one answer
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OpenStudy (anonymous):
which is all ready done
OpenStudy (rizags):
Wait up, is it \[A= \frac{x+y+z}{3}\] or \[A= x+ y + \frac{z}{3}\]
OpenStudy (anonymous):
the first one
OpenStudy (rizags):
ahh, then, yes your answer is correct
OpenStudy (rizags):
first multiply both sides by 3 to get \[3A = x+y+z\]
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OpenStudy (rizags):
then subtract x and z \[3A-x-z=y\]
OpenStudy (anonymous):
Thats the part i get confused where am i subtracting x and z?
OpenStudy (anonymous):
y=\[\frac{ a-z-x }{ 3 }\]
OpenStudy (anonymous):
no your not
OpenStudy (rizags):
from here: \[3A = x+y+z\] you subtract x and z
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OpenStudy (anonymous):
no you divide by three to get y alone
OpenStudy (anonymous):
ohhh i see because youre trying to get the y alone
OpenStudy (anonymous):
yah
OpenStudy (anonymous):
and what ever is on the other side is y
OpenStudy (anonymous):
okay thank you both :)
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OpenStudy (anonymous):
no problem