Question

Can someone just help me solve this please?? i need an extraneous solution and it solved. i chose this but im not sure its correct.
2√x+5+7=4

Answer 1

Is that the original equation?

Answer 2

no it said to choose your own using a√x+b+c=d

Answer 3

Ah I understand hold for a minute please

Answer 4

okay.

Answer 5

I dont think it has an extraneous solution because I got x=16

Answer 6

well could you help me find one with one please? using the a√x+b+c=d formula thingy

Answer 7

Sure!

Answer 8

So you do understand what an extraneous solution is correct?

Answer 9

i think it is how it solves the problem but if you plug it back in it doesnt work out

Answer 10

like if you solve the radical but if you plug it in to check the answer will not work out

Answer 11

Yes that is correct! :)

Answer 12

im not sure how to like create and solve a radical like that though... ;(

Answer 13

Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model.

a√x+b+c=d

Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

Answer 14

is it \[a \sqrt{x+b+c}=d\] or \[a \sqrt{x} + b + c=d\]

Answer 15

try something like
\[ \sqrt{x+2} + 1 = -1 \]

Answer 16

the first one @stefrheart

Answer 17

@phi the only problem is is that i don't know how to solve that equation to check if it has an extraneous solution

Answer 18

To solve that all you need to do is subtract the one on both sides to create
\[\sqrt{x+2}=-2\]
and then square both sides
\[(\sqrt{x+2})^{2}=(-2)^{}\]
and then solve

Answer 19

just for phi's equation

Answer 20

x=-8 @stefrheart

Answer 21

@kenzi041

Answer 22

i dont even know. i never learned radicals

Answer 23

oh you dont know what a radical is or how to work with it?

Answer 24

we had a large learning gap because they changed curriculums

Answer 25

not really.

Answer 26

Ah okay so you should learn what a radical is first then, before proceeding with the problem

Answer 27

oh.

Answer 28

It would make alot more sense before solving this. Do you know what a \[x ^{2}\] is? It would be easier to teach you if you knew what it is

Answer 29

x squared?

Answer 30

yes you know what to do with it if someone gave you the equation \[4^{2}\] ?

Answer 31

16, i know like how to do that i just dont understand how to use like larger equations like a√x+b+c=d

Answer 32

Ah okay so you know how to do that. Well the larger equations are just the same ting as a regular square root.

Answer 33

okay, so how do i find one with an extraneous solution

Answer 34

because i have one for without but i just need one with one

Answer 35

I think I may have one hold on

Answer 36

ok

Answer 37

x=-8 u have check in the equation ans see it

Answer 38

Whats the extraneous solution then? @dinamix

Answer 39

like how do you plug it in to check if it has one @dinamix

Answer 40

Try this for help
https://www.khanacademy.org/math/algebra2/radical-equations-and-functions/radical-equations/e/extraneous-solutions-to-radical-equations

Answer 41

i already tried but it was in a different format than what the question asked

Answer 42

Yeah I noticed
​​

Answer 43

and i got more confused..

Answer 44

Hmmm im trying to figure out equations because in order for it to have both an actual and extraneous there needs to be 2 solutions which is a \[x ^{2}+bx+c\]
unless we can do that you cant get both an actual and extraneous

Answer 45

no it needs to just be a extraneous solution.. you write two problems and one should be regular and one should have an extraneous solution

Answer 46

Ohhh then I already have one then

Answer 47

\[-5\sqrt{-3x-5}=-25\]

Answer 48

but doesnt it have to be x+b+c=d

Answer 49

if you wwant it you can just put -3x+-5+0 for under the radical

Answer 50

okay, one sec im checking a problem i just did.

Answer 51

I will be back in a few minutes

Answer 52

i think i found one, the problem i chose originally

Answer 53

and okay

Answer 54

AH okay

Answer 55

Message me if need you still need help

Answer 56

thanks for helping

Answer 57

how do i give u a medal?

Answer 58

@kenzi041 click the best response

Answer 59

@stefrheart i failed, but thanks anyway

Answer 60

Aw im sorry :( @kenzi041