Mathematics
18 Online
OpenStudy (anonymous):
Translation problems please help..
Twenty less than twelve percent of a number minus the sum of twice the number and negative fifteen
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OpenStudy (anonymous):
.12x - 2x 20- -15
?? is this correct
OpenStudy (anonymous):
@jim_thompson5910 ?
OpenStudy (madhu.mukherjee.946):
let the number be x
OpenStudy (anonymous):
oh yes
OpenStudy (anonymous):
wouldnt the 20 go next to the 15? since its less than?
or do i just solve from there?
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OpenStudy (anonymous):
the answer sheet says its -18.8x - 35
and i figured out how to get the 35 but i cant seem to figure out -18.8 bc all i get is 1.88
OpenStudy (anonymous):
okay thanks :)
OpenStudy (madhu.mukherjee.946):
is mine not matching with your answer
OpenStudy (anonymous):
im not sure.
OpenStudy (madhu.mukherjee.946):
@jim_thompson5910
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OpenStudy (madhu.mukherjee.946):
hey sorry i've got your answer
OpenStudy (madhu.mukherjee.946):
it will be 12x/100-20-2x-15
OpenStudy (madhu.mukherjee.946):
then you will get
12x-2000-200x-1500/100
OpenStudy (madhu.mukherjee.946):
i'm so sorry ...i did not want to misguide you:(
OpenStudy (anonymous):
so you just multiply everything?
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OpenStudy (anonymous):
its okay :)
OpenStudy (madhu.mukherjee.946):
no
jimthompson5910 (jim_thompson5910):
when I translated, I got `(0.12x-20)-(2x-15)` which simplifies to `-1.88x -5`
OpenStudy (madhu.mukherjee.946):
you got to take the lcm 100
OpenStudy (anonymous):
hmm
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OpenStudy (madhu.mukherjee.946):
|dw:1441003854864:dw|
OpenStudy (madhu.mukherjee.946):
do you understand?
OpenStudy (anonymous):
yes in a way
OpenStudy (madhu.mukherjee.946):
if you have confusion then pls ask
OpenStudy (anonymous):
okay so i divided 188/100 and its 1.88 do i move the decimal?
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OpenStudy (anonymous):
other than that i understand it :)
OpenStudy (madhu.mukherjee.946):
no it will be 1.88 and not 18.8:)
OpenStudy (anonymous):
oh okay then i understand thanks so much! :)
OpenStudy (madhu.mukherjee.946):
i rechecked it many times its correct:)
OpenStudy (madhu.mukherjee.946):
your welcome
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OpenStudy (anonymous):
:)