Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Can someone please help me simplify these radical expressions? Screen shots included! Medal and fan!

OpenStudy (anonymous):

OpenStudy (sohailiftikhar):

ok wright first one \[\sqrt{45n^5}\]

OpenStudy (anonymous):

3√6 √n^5

OpenStudy (anonymous):

3√5***

OpenStudy (sohailiftikhar):

now split the expression ... yes it will be 3 n^2\[\sqrt{5n}\]

OpenStudy (sohailiftikhar):

\[3n^2 \sqrt{5n}\]

OpenStudy (sohailiftikhar):

now take second .. \[\sqrt{75}+\sqrt{3}\]

OpenStudy (anonymous):

ok

OpenStudy (sohailiftikhar):

\[\sqrt{25\times 3}+\sqrt{3}\]

OpenStudy (sohailiftikhar):

\[5\sqrt{3}+\sqrt{3}\]

OpenStudy (sohailiftikhar):

now what you think?

OpenStudy (anonymous):

wait we're on problem 2 now? you simplified √25x 3?

OpenStudy (sohailiftikhar):

yes

OpenStudy (sohailiftikhar):

\[\sqrt{75}=5\sqrt{3}\]

OpenStudy (sohailiftikhar):

so \[\sqrt{75}+\sqrt{3}=5\sqrt{3}+\sqrt{3}=6\sqrt{3}\]

OpenStudy (anonymous):

ohh ok

OpenStudy (sohailiftikhar):

now take third ..

OpenStudy (anonymous):

wait

OpenStudy (sohailiftikhar):

what ?

OpenStudy (anonymous):

So this is correct? 6.) √75 + √3 √25 * 3 + √3 5√3 + √3 = 6√3

OpenStudy (anonymous):

Okay now for 3

OpenStudy (sohailiftikhar):

can you do it ?

OpenStudy (sohailiftikhar):

ok

OpenStudy (anonymous):

@sohailiftikhar sorry I lost connection please help me with the last one

OpenStudy (unklerhaukus):

are you up to question 7)?

OpenStudy (anonymous):

yes @UnkleRhaukus

OpenStudy (unklerhaukus):

\[\sqrt7(\sqrt{14}+\sqrt3)\]factor the 14

OpenStudy (unklerhaukus):

like 75 factors to be 3*25

OpenStudy (unklerhaukus):

14 = ? * ?

OpenStudy (unklerhaukus):

what numbers multiply to equal 14?

OpenStudy (anonymous):

or factoring = breaking it down

OpenStudy (anonymous):

2*7 lol

OpenStudy (unklerhaukus):

\[\sqrt7(\sqrt{14}+\sqrt3)\\ =\sqrt7(\sqrt{2\times7}+\sqrt3)\\ =\sqrt7(\sqrt2\sqrt7+\sqrt3)\\ =\] now distribute. (multiply the term out the front of the parentheses, by all the terms inside )

OpenStudy (unklerhaukus):

huh?

OpenStudy (sohailiftikhar):

so you here ?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!