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find the limit as x approaches 1 of ((6x^4)-6)/(2x-2)
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factoring time!
\[\lim_{x \rightarrow 1}\frac{ 6x ^{4}-6 }{ 2x-2 }\]
\[6x^4-6 \\ 6(x^4-1) \\ 6(x^2-1)(x^2+1) \text{ by differece of squares }\] can you use difference of squares again bet you will see a common factor on top and bottom
yup or if you know the l'hospitals theorem then you could use that too.
keep in mind that \(1 = 1^2, 1^3,1^4, 1^5, 1^1000....\)
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hmm \(1^{1000}\) rather... anyhow \((x^4-1) = (x^4-1^4)\) thus
@clara1223 u must find it =12 this limit
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