Algebra
7 Online
OpenStudy (anonymous):
okay help with this problem and then one more and I wont need anymore help tonight.
(2-3i(3-i)-(4-i)(4+i)
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OpenStudy (anonymous):
\[(2-3i)(3-i)-(4-i)(4+i)\]
OpenStudy (anonymous):
(2-3i)(3-i)-(4-i)(4+i)
OpenStudy (anonymous):
theres supposed to be one more parenthases after 3i
OpenStudy (anonymous):
am i foiling this or is that not the right way to go about this problem?
jimthompson5910 (jim_thompson5910):
you can FOIL or use the table like last time. Which option works best for you?
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OpenStudy (anonymous):
foil the table is a little confusing.
jimthompson5910 (jim_thompson5910):
ok what do you get when you FOIL (2-3i)(3-i)
OpenStudy (bradely):
(2 -3i)(3-i)-(4-i)(4+i)
(2)(3-i)-(3i)(3-i)-(4^2-i^2)
Multiply find the value
Note i^2 = -1
Source: mathskey.com
OpenStudy (anonymous):
3-11i
jimthompson5910 (jim_thompson5910):
correct
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jimthompson5910 (jim_thompson5910):
how about `(4-i)(4+i)` ?
OpenStudy (anonymous):
that is 15
OpenStudy (anonymous):
brb
jimthompson5910 (jim_thompson5910):
not 15, but you are close
jimthompson5910 (jim_thompson5910):
try again
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
where did i go wrong with my problem i will show you my work.
OpenStudy (bradely):
(4-i)(4+i)
(a-b)(a+b) =a^2-b^2
4^2 -i^2
16-(-1)=17
OpenStudy (anonymous):
could the answer be 187i+51?
OpenStudy (anonymous):
|dw:1441072256502:dw|
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jimthompson5910 (jim_thompson5910):
i^2 is -1
so \(\Large 16-\color{red}{i^2}\) turns into \(\Large 16-\color{red}{(-1)}\)
OpenStudy (anonymous):
im not sure @sayomi
jimthompson5910 (jim_thompson5910):
Do you see what I mean @huntergirl1 ?
OpenStudy (anonymous):
yes now i do @jim_thompson5910
jimthompson5910 (jim_thompson5910):
ok great, so
16-(-1) = 16+1 = 17
---------------------
\[\large \color{red}{(2-3i)(3-i)}-\color{blue}{(4-i)(4+i)} =\color{red}{3-11i}-\color{blue}{17} = -14-11i\]
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OpenStudy (anonymous):
@sayomi you were correct and yes @jim_thompson5910 i do understand
jimthompson5910 (jim_thompson5910):
I'm glad it's making sense
OpenStudy (anonymous):
so the ending result is 51-187i
OpenStudy (anonymous):
okay do you wnt me to start a new window for the next problem? or to place it here?
jimthompson5910 (jim_thompson5910):
how are you getting `51-187i` ?
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jimthompson5910 (jim_thompson5910):
I wrote the answer above
OpenStudy (anonymous):
bc you put 17 back into the problem
jimthompson5910 (jim_thompson5910):
are you saying that they wanted you to multiply `(2-3i)(3-i)` and `(4-i)(4+i)` ??
OpenStudy (anonymous):
actually i put those answers both into the website they were both incorrect
OpenStudy (anonymous):
hwy was the answer supposed to be -14-11i?
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OpenStudy (anonymous):
why
jimthompson5910 (jim_thompson5910):
because the 3 and -17 combine to -14
jimthompson5910 (jim_thompson5910):
(3-11i) - (17) = 3-11i - 17 = (3-17) + (-11i) = -14 - 11i
OpenStudy (anonymous):
oh okay.
OpenStudy (anonymous):
will you be on to check a few more problems before I submit them?
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jimthompson5910 (jim_thompson5910):
sure
OpenStudy (anonymous):
thank you!!!!!!!!!!!!
jimthompson5910 (jim_thompson5910):
no problem
OpenStudy (anonymous):
okay i have one to check its similar to the last problem
OpenStudy (anonymous):
|dw:1441074082197:dw|
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OpenStudy (anonymous):
what did i do wrong?
jimthompson5910 (jim_thompson5910):
you didn't foil correctly
OpenStudy (anonymous):
okay i guess the sqrt part mixed me up
OpenStudy (anonymous):
i also tried the box method too
jimthompson5910 (jim_thompson5910):
|dw:1441074547608:dw|
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jimthompson5910 (jim_thompson5910):
what we do is make a 2x2 box
2 rows and 2 columns
the terms of each factor will go along the outside like this
|dw:1441074595637:dw|