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Algebra 7 Online
OpenStudy (anonymous):

okay help with this problem and then one more and I wont need anymore help tonight. (2-3i(3-i)-(4-i)(4+i)

OpenStudy (anonymous):

\[(2-3i)(3-i)-(4-i)(4+i)\]

OpenStudy (anonymous):

(2-3i)(3-i)-(4-i)(4+i)

OpenStudy (anonymous):

theres supposed to be one more parenthases after 3i

OpenStudy (anonymous):

am i foiling this or is that not the right way to go about this problem?

jimthompson5910 (jim_thompson5910):

you can FOIL or use the table like last time. Which option works best for you?

OpenStudy (anonymous):

foil the table is a little confusing.

jimthompson5910 (jim_thompson5910):

ok what do you get when you FOIL (2-3i)(3-i)

OpenStudy (bradely):

(2 -3i)(3-i)-(4-i)(4+i) (2)(3-i)-(3i)(3-i)-(4^2-i^2) Multiply find the value Note i^2 = -1 Source: mathskey.com

OpenStudy (anonymous):

3-11i

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

how about `(4-i)(4+i)` ?

OpenStudy (anonymous):

that is 15

OpenStudy (anonymous):

brb

jimthompson5910 (jim_thompson5910):

not 15, but you are close

jimthompson5910 (jim_thompson5910):

try again

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

where did i go wrong with my problem i will show you my work.

OpenStudy (bradely):

(4-i)(4+i) (a-b)(a+b) =a^2-b^2 4^2 -i^2 16-(-1)=17

OpenStudy (anonymous):

could the answer be 187i+51?

OpenStudy (anonymous):

|dw:1441072256502:dw|

jimthompson5910 (jim_thompson5910):

i^2 is -1 so \(\Large 16-\color{red}{i^2}\) turns into \(\Large 16-\color{red}{(-1)}\)

OpenStudy (anonymous):

im not sure @sayomi

jimthompson5910 (jim_thompson5910):

Do you see what I mean @huntergirl1 ?

OpenStudy (anonymous):

yes now i do @jim_thompson5910

jimthompson5910 (jim_thompson5910):

ok great, so 16-(-1) = 16+1 = 17 --------------------- \[\large \color{red}{(2-3i)(3-i)}-\color{blue}{(4-i)(4+i)} =\color{red}{3-11i}-\color{blue}{17} = -14-11i\]

OpenStudy (anonymous):

@sayomi you were correct and yes @jim_thompson5910 i do understand

jimthompson5910 (jim_thompson5910):

I'm glad it's making sense

OpenStudy (anonymous):

so the ending result is 51-187i

OpenStudy (anonymous):

okay do you wnt me to start a new window for the next problem? or to place it here?

jimthompson5910 (jim_thompson5910):

how are you getting `51-187i` ?

jimthompson5910 (jim_thompson5910):

I wrote the answer above

OpenStudy (anonymous):

bc you put 17 back into the problem

jimthompson5910 (jim_thompson5910):

are you saying that they wanted you to multiply `(2-3i)(3-i)` and `(4-i)(4+i)` ??

OpenStudy (anonymous):

actually i put those answers both into the website they were both incorrect

OpenStudy (anonymous):

hwy was the answer supposed to be -14-11i?

OpenStudy (anonymous):

why

jimthompson5910 (jim_thompson5910):

because the 3 and -17 combine to -14

jimthompson5910 (jim_thompson5910):

(3-11i) - (17) = 3-11i - 17 = (3-17) + (-11i) = -14 - 11i

OpenStudy (anonymous):

oh okay.

OpenStudy (anonymous):

will you be on to check a few more problems before I submit them?

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

thank you!!!!!!!!!!!!

jimthompson5910 (jim_thompson5910):

no problem

OpenStudy (anonymous):

okay i have one to check its similar to the last problem

OpenStudy (anonymous):

|dw:1441074082197:dw|

OpenStudy (anonymous):

what did i do wrong?

jimthompson5910 (jim_thompson5910):

you didn't foil correctly

OpenStudy (anonymous):

okay i guess the sqrt part mixed me up

OpenStudy (anonymous):

i also tried the box method too

jimthompson5910 (jim_thompson5910):

|dw:1441074547608:dw|

jimthompson5910 (jim_thompson5910):

what we do is make a 2x2 box 2 rows and 2 columns the terms of each factor will go along the outside like this |dw:1441074595637:dw|

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