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find the limit as x approaches 3 of (1)/(x-3)
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\[\lim_{x \rightarrow 3}\frac{ 1 }{ x-3 }\]
What does the denominator do as x approaches 3?
@tkhunny it becomes 0...?
please help! i have this and one more limit problem and i'm done and ive been studying all day and im exhausted and I just don't understand these.
I suggest looking at a table of values specifically x values close to x = 3 like x = 3.1, x = 3.01, x = 3.001 and x = 2.99, x = 2.999, x = 2.9999, etc
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|dw:1441074112182:dw|
I already know that the limit doesnt exist I just need to know how to prove it
|dw:1441074140948:dw|
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