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When F is defined for x ≥ −6 by F(x)= integral from -6 to x (6t^2+5t-1)/(3+4t^2) dt. determine the largest interval(s) on which F is decreasing.
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have you found F'(x)?
no, going to do it now
F'(x)= (6x^2+5x-1)/(3+4x^2)
@freckles so how do I find where F(x) is increasing?
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the function F is increasing when F' is positive
the function F is decreasing when F' is negative
solve the inequality \[\frac{6x^2+5x-1}{3+4x^2} <0\]
got it, thank you
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