Calculate a chain of 4x4 matrices (don’t multiply them together) that will rotate
points about the vector A = [(.5)^1/2, 1.73, (.5)^1/2]. Show your work.
Helpful trig evaluations: tan (60 deg) = 1.73; tan (45 deg) = 1.0

Question

Calculate a chain of 4x4 matrices (don’t multiply them together) that will rotate
points about the vector A = [(.5)^1/2, 1.73, (.5)^1/2]. Show your work.
Helpful trig evaluations: tan (60 deg) = 1.73; tan (45 deg) = 1.0

phi · Answer

I know it's possible, but I don't remember the details.
How much do you know ?

phi · Answer

This gives an algorithm http://inside.mines.edu/fs_home/gmurray/ArbitraryAxisRotation/ it looks messy

anonymous · Answer

attachment

anonymous · Answer

have a look

phi · Answer

your vector A in spherical coords means
phi = 45  and theta= 60
|dw:1441136301303:dw|

phi · Answer

according to the link, the steps are 
1 rotate 60º so the vector is in the xz plane
2 then rotate that by 45 so it points in the z direction
3 now do the rotation you want
4,5 then undo step 2 and then step 1