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(sec(x)+tan(x))((1-sin(x))/cos(x))=1
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Use sinx/cosx=tanx
And secx=1/cosx
\[(\frac{ 1 }{ cosx }+\frac{ sinx }{ cosx })(\frac{ 1-sinx }{ cosx })=1\]\[(\frac{ 1+sinx }{ cosx })(\frac{ 1-sinx }{ cosx })=1\]\[\frac{ 1-\sin ^{2}x }{ \cos ^{2}x }=1\]...now use the Pythagorean identity to simplify
i have already done that. now what
Solve the pythagorean identity for cos^2x and see what you get.
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how do you use the Pythagorean identity for cos^2x
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